Interfacing RAM and ROM both at a time with 8085:
Here ROM with 32 kb and RAM with 64kb has been used.
32kb = 32768bytes is equal to
2^15
and
64kb = 65536bytes is equal to 2^16
So it is clear that 15 address lines are required for interfacing of ROM and 16 address lines are required for interfacing of RAM. As we know that there are only 16 address lines in 8085 Microprocessor. But we need 16+15 = 31 lines.
Think!!!!!!!!
How it may be possible???
To See the answer CliCK Here:
Here ROM with 32 kb and RAM with 64kb has been used.
32kb = 32768bytes is equal to
2^15
and
64kb = 65536bytes is equal to 2^16
So it is clear that 15 address lines are required for interfacing of ROM and 16 address lines are required for interfacing of RAM. As we know that there are only 16 address lines in 8085 Microprocessor. But we need 16+15 = 31 lines.
Think!!!!!!!!
How it may be possible???
To See the answer CliCK Here:
With Microprocessor 16KB of ROM and 4 chips of 8KB RAM are interfaced.
ReplyDeleteDraw connection diagram and show memory map.